Language
Compiler
Options
$ foo(123456) T = Type<int> type of iParam = Type<int&&>
foo(123456) T = Type<int> type of iParam = Type<int&&>
constRef(123456) T = Type<int> type of iParam = Type<int const&>
constRef(123456) T = Type<int> type of iParam = Type<int const&>
constRef(123456) T = Type<int> type of iParam = Type<int const&>
ref(123456) T = Type<int> type of iParam = Type<int&>
ptr(123456) T = Type<int> type of iParam = Type<int*>
constPtr(123456) T = Type<int> type of iParam = Type<int const*>
Exit Code:
0